Question

(2x-3)(3x-1)=-3(3x-1)

Answer 1

`(2x-3)(3x-1)=-3(3x-1)`

`<=>(2x-3)(3x-1)+3(3x-1)=0`

`<=>(3x-1)(2x-3+3)=0`

`<=>(3x-1)*2x=0`

\(< =>\left[{}\begin{matrix}3x-1=0\\2x=0\end{matrix}\right.\\ < =>\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=0\end{matrix}\right.\)

Answer 2

(2x - 3)(3x - 1) = -3(3x - 1)

(2x - 3)(3x - 1) + 3(3x - 1) = 0

(3x - 1)(2x - 3 + 3) = 0

3x - 1 = 0 hoặc 2x = 0

*) 3x - 1 = 0

3x = 1

x = 1/3

*) 2x = 0

x = 0

Vậy S = {0; 1/3}