(2x-16)^7 = 128
1. Tìm x ∈ N sao cho:
a) (x - 1)2 = 1 b) 72x - 6 = 49 c) (2x - 16)7 = 128
b, 2x + 15 = -27 | |
c, -765 – (305 + x) = 100 |
d, 2x : 4 = 16 e)128 – 3( x + 4 ) = 23 |
7/2 + 7/4 +7/8 + 7/16 + 7/32 + 7/64 + 7/128 +7/256 + ...
( 2x + 1) mũ 3 = 96
16 mũ x < 128 mũ4
a,2^x+2-2^x=96
b720:[41-(2x-5)]=2^3.5
c,16^x<128^4
2x-7=5
128-3.(X+4)=23
- 3 ( - x + 1 ) - 2 ( x + 7 ) - 32 = - ( - 2x - 9 ) - 128
Tìm x:
A. ( x - 5 )² = 16
B. 4^x + 33 = 7²
C. 2^x . 4 = 128
D. 5^x . 3 - 75 = 0