\(\left|2x-1\right|=5\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-2\right\}\)
\(| 2x - 1 | = 5 \)
\(\rightarrow | 2x - 1 | = | 5| = | -5 |\)
\(\rightarrow \begin{cases} 2x - 1 = 5\\2x - 1 = -5 \end{cases}\)
\(\rightarrow \begin{cases} 2x = 6\\2x = -4 \end{cases}\)
\(\rightarrow\begin{cases} x = 3\\x = -2 \end{cases}\)
\(Vậy \) \(x \in \) { \(3 ; -2 \) } \(thì \) \(| 2x-1| = 5\)