Question

(2x – 1)² – (x+3)² = 0

Answer 1

\(\Leftrightarrow\left(2x-1-x-3\right)\left(2x-1+x+3\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(3x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{2}{3}\end{matrix}\right.\)

Answer 2

tìm x nha

Answer 3

\(\left(2x-1\right)^2-\left(x+3\right)^2=0\\\Rightarrow\left(2x-1-x-3\right)\left(2x-1+x+3\right)=0\\ \Rightarrow\left(x-4\right)\left(3x+2\right)=0 \Rightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{2}{3}\end{matrix}\right.\)