(2x + 10)(3x - 12) = 0
2(x + 5) . 3(x - 4) = 0
6(x + 5)(x - 4) = 0
=> (x + 5)(x - 4) = 0
=> x + 5 =0 hoặc x - 4 = 0
=> x = -5 hoặc x = 4
Vậy x E {-5; 4}
\(\left(2x+10\right)\left(3x-12\right)=0.\Leftrightarrow\left[{}\begin{matrix}2x+10=0.\\3x-12=0.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-5.\\x=4.\end{matrix}\right.\)
Vậy \(x\in\left\{-5;4\right\}.\)
Tham khảo bài làm:
(2x + 10)(3x - 12) = 0
2(x + 5) . 3(x - 4) = 0
6(x + 5)(x - 4) = 0
=> (x + 5)(x - 4) = 0
=> x + 5 =0 hoặc x - 4 = 0
=> x = -5 hoặc x = 4
Vậy x E {-5; 4}
(2x + 10)(3x - 12) = 0
2(x + 5) . 3(x - 4) = 0
6(x + 5)(x - 4) = 0
=> (x + 5)(x - 4) = 0
=> x + 5 =0 hoặc x - 4 = 0
=> x = -5 hoặc x = 4
Vậy x E {-5; 4}