\(\left(2\sqrt{5}-\sqrt{7}\right)^2=20-4\sqrt{35}+7=27-4\sqrt{35}\)
Ta có:
\(\left(2\sqrt{5}-\sqrt{7}\right)^2\)
\(=\left(2\sqrt{5}\right)^2-2.2\sqrt{5}.\sqrt{7}+\left(\sqrt{7}\right)^2\)
\(=4.5-4\sqrt{5.7}+7\)
\(=20-4\sqrt{35}+7\)
\(=27-4\sqrt{35}\)