Question

(2n + 16) chia hết cho (n+1) tìm số tn n 

Answer 1

\(\left(2n+16\right)⋮\left(n+1\right)\)

\(\Rightarrow2\left(n+1\right)+14⋮\left(n+1\right)\)\(\Rightarrow\left(n+1\right)\inƯ\left(14\right)=\left\{1;-1;2;-2;7;-7;14;-14\right\}\)

Do \(n\in N\)

\(\Rightarrow n\in\left\{0;1;6;13\right\}\)

Answer 2

(2n+16)⋮(n+1)

⇒2(n+1)+14⋮(n+1)⇒(n+1)∈Ư(14)={1;−1;2;−2;7;−7;14;−14}

Do 

 

Answer 3

Ta có: \(2n+16⋮n+1\)

\(\Leftrightarrow n+1\in\left\{1;-1;2;-2;7;-7;14;-14\right\}\)

hay \(n\in\left\{0;-2;1;-3;6;-8;13;-15\right\}\)