\(\dfrac{2}{7}x\) - \(\dfrac{5}{2}\) + 2 = \(\dfrac{1}{4}\) + \(\dfrac{1}{7}x\)
\(\dfrac{2}{7}x\) - \(\dfrac{1}{7}\)\(x\) = \(\dfrac{1}{4}\) + \(\dfrac{5}{2}\) - 2
\(\dfrac{1}{7}x\) = \(\dfrac{1}{4}\) + \(\dfrac{10}{4}\) - \(\dfrac{8}{4}\)
\(\dfrac{1}{7}\)\(x\) = \(\dfrac{11}{4}-\dfrac{8}{4}\)
\(\dfrac{1}{7}x=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}:\dfrac{1}{7}\)
\(x=\dfrac{21}{4}\)
Vậy \(x=\dfrac{21}{4}\)
\(\dfrac{2}{7}x-\dfrac{5}{2}+2=\dfrac{1}{4}+\dfrac{1}{7}x\)
\(\Rightarrow\dfrac{2}{7}x-\dfrac{1}{7}x=\dfrac{1}{4}+\dfrac{5}{2}-2\)
\(\Rightarrow x\left(\dfrac{2}{7}-\dfrac{1}{7}\right)=\dfrac{1}{4}+\dfrac{10}{4}-\dfrac{8}{4}\)
\(\Rightarrow x.\dfrac{1}{7}=\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{3}{4}:\dfrac{1}{7}\)
\(\Rightarrow x=\dfrac{3}{4}.7\)
\(\Rightarrow x=\dfrac{21}{4}\)
Vậy \(x=\dfrac{21}{4}\)