\(\dfrac{2^6\cdot6+4^5}{13\cdot2^7-14\cdot2^6}=\dfrac{2^6\cdot6+2^{10}}{13\cdot2^7-14\cdot2^6}=\dfrac{2^6\cdot\left(6+2^4\right)}{2^6\cdot\left(13\cdot2-14\right)}\\ =\dfrac{6+2^4}{13\cdot2-14}\\ =\dfrac{6+16}{26-14}\\ =\dfrac{22}{12}=\dfrac{11}{6}\)