Question

(2/4x+y)^2

Answer 1

\(\left(\dfrac{2}{4}x+y\right)^2\\ =\left(\dfrac{2}{4}x\right)^2+2.\dfrac{2}{4}x.y+y^2\\ =\dfrac{4}{16}x^2+\dfrac{2}{2}xy+y^2\\ =\dfrac{1}{4}x^2+xy+y^2\)

Answer 2

\(\left(\dfrac{2}{4}x+y\right)^2\)

\(=\left(\dfrac{1}{2}x+y\right)^2\)

\(=\dfrac{1}{4}x^2+xy+y^2\)