`#3107.101107`
\(\dfrac{2^{4-x}}{16^5}=32^6\\ \dfrac{2^{4-x}}{\left(2^4\right)^5}=\left(2^5\right)^6\\ \dfrac{2^4\div2^x}{2^{20}}=2^{30}\\ 2^4\div2^x=2^{30}\cdot2^{20}\\ 2^4\div2^x=2^{50}\\ 2^x=2^4\div2^{50}\\ 2^x=2^{-46}\\ x=-46\)
\(\dfrac{2^{4-x}}{16^5}\) = 326
24 - \(x\) = (25)6.(24)5
24 - \(x\) = 230.220
24 - \(x\) = 250
4 - \(x\) = 50
\(x\) = 4 - 50
\(x\) = - 46
Vậy \(x\) = - 46