Question

(2/3x-3)^2

Answer 1

\(\left(\dfrac{2}{3}x-3\right)^2\\ =\left(\dfrac{2}{3}x\right)^2-2.\dfrac{2}{3}x.3+3^2\\ =\dfrac{4}{9}x^2-4x+9\)

Answer 2

\(\left(\dfrac{2}{3}x-3\right)^2\)

\(=\left(\dfrac{2}{3}x\right)^2-2.\dfrac{2}{3}x.3+3^2\)

\(=\dfrac{4}{9}x^2-2.\dfrac{2}{3}x.3+3^2\)

\(=\dfrac{4}{9}x^2-4x+3^2\)

\(=\dfrac{4}{9}x^2-4x+9\)