\(\dfrac{23}{4}:3+2\dfrac{1}{4}\times\dfrac{1}{3}-1\dfrac{1}{4}:3\\ =\dfrac{23}{12}+\dfrac{9}{4}\times\dfrac{1}{3}-\dfrac{5}{4}:3\\ =\dfrac{23}{12}+\dfrac{9}{12}-\dfrac{5}{12}\\ =\dfrac{23+9-5}{12}\\ =\dfrac{27}{12}\)
\(\dfrac{23}{12}+\dfrac{3}{4}-\dfrac{5}{12}=\dfrac{32}{12}-\dfrac{5}{12}=\dfrac{27}{12}\)