2312 + 2132 . 2 + 2 : 2= 2312 + 4264 +1 =6577
2312 + 2132 . 2 + 2 : 2= 2312 + 4264 +1 =6577
2312 + 2132 . 2 + 2 : 2= 2312 + 4264 +1 =6577
2312 + 2132 . 2 + 2 : 2= 2312 + 4264 +1 =6577
tính : 1^2-2^2+3^2-4^2+...-2004^2+2005^2
b) (2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)-2^64
bài 6:tính nhanh
7)1\(^2\)-2\(^2\)+3\(^2\)-4\(^2\)+....-2004\(^2\)+2005\(^2\)
8) (2+1)(2\(^2\)+1)(2\(^4\)+1)(2\(^8\)+1)(2\(^{16}\)+1)(2\(^{32}\)+1)-2\(^{64}\)
tính
1^2+3^2+5^2+.....+97^2+99^2
1^2-2^2+3^2-4^2+5^2-...........-98^2+99^2-100^2
Viết các biểu thức sau dưới dạng tổng
a, (3+x*y^2)^2
b, (a-b^2)*(a+b^2)
c, (a^2+2*a+3)*(a^2+2*a-3)
d, (a^2+2*a+3)*(a^2-2*a-3)
e, (a^2-2*a+3)*(a^2+2*a-3)
f, (a^2+2*a+3)*(a^2-2*a+3)
g, (-a^2-2*a+3)*(-a^2-2*a+3)
h, (a^2+2*a)*(2*a-a^2)
( 10^2 + 8^2 + 6^2 + 4^2 + 2^2 + 1^2 ) - ( 9^2 + 7^2 + 5^2 + 3^2 + 1^2 )
cho x,y,z thỏa mãn \(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=0\)
\(M=\frac{x^2\cdot y^2.z^2}{x^2\cdot y^2+y^2\cdot z^2-x^2\cdot z^2}+\frac{x^2\cdot y^2\cdot z^2}{y^2\cdot z^2+x^2.z^2-x^2\cdot y^2}+\frac{x^2\cdot y^2\cdot z^2}{x^2.y^2+x^2\cdot z^2-y^2\cdot z^2}\)
(10^2+8^2+6^2+4^2+2^2)-(9^2+7^2+5^2+3^2+1^2)
(10^2+8^2+6^2+4^2+2^2)-(9^2+7^2+5^2+3^2+1^2)
(10^2+8^2+6^2+4^2+2^2)-(9^2+7^2+5^2+3^2+1^2)