\(\dfrac{2}{3}+\dfrac{-3}{5}=\dfrac{10}{15}+\dfrac{-9}{15}=\dfrac{1}{15}\)
\(\dfrac{2}{9}-\left(\dfrac{1}{20}+\dfrac{2}{9}\right)=\dfrac{2}{9}-\dfrac{1}{20}-\dfrac{2}{9}=\left(\dfrac{2}{9}-\dfrac{2}{9}\right)-\dfrac{1}{20}=0-\dfrac{1}{20}=\dfrac{-1}{20}\)
\(\dfrac{3}{5}.\dfrac{-1}{2}=\dfrac{3.-1}{5.2}=\dfrac{-3}{10}\)