`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2}{3}-\dfrac{5}{6}+\dfrac{1}{12}\)
`=`\(\dfrac{8}{12}-\dfrac{10}{12}+\dfrac{1}{12}\)
`=`\(-\dfrac{1}{12}\)
_____
\(\dfrac{3}{4}+\dfrac{3}{16}-\dfrac{1}{2}?\)
`=`\(\dfrac{12}{16}+\dfrac{3}{16}-\dfrac{8}{16}\)
`=`\(\dfrac{7}{16}\)
_____
\(\dfrac{2}{5}-\dfrac{4}{7}+\dfrac{1}{2}\)
`=`\(\dfrac{2}{5}+\dfrac{1}{2}-\dfrac{4}{7}\)
`=`\(\dfrac{4}{10}+\dfrac{5}{10}-\dfrac{4}{7}\)
`=`\(\dfrac{9}{10}-\dfrac{4}{7}\)
`=`\(\dfrac{63}{70}-\dfrac{40}{70}=\dfrac{23}{70}\)