\(2\sqrt{3}+3\sqrt{3}-8\sqrt{3}=-3\sqrt{3}\)
\(2\sqrt{3}+3\sqrt{3}-8\sqrt{3}=-3\sqrt{3}\)
√27-2√3+2√48-3√75
2√3(√27+2√48-√75)
căn 27 -3 căn 48 +2 căn 108 - căn ( 2-căn 3 )^2
4√27-2√48 +3√12-√75
rút gọn biểu thức
E=2\(\sqrt{3}\)+3\(\sqrt{27}\)-\(\sqrt{300}\)
F=3\(\sqrt{2}\)+4\(\sqrt{18}\)
G=2\(\sqrt{3}\)-4\(\sqrt{27}\)+5\(\sqrt{48}\)
H=(3\(\sqrt{50}\)-5\(\sqrt{18}\)+3\(\sqrt{8}\))\(\sqrt{2}\)
Rút gọn các biểu thức sau a)√27-✓12+✓48-5✓3 b)5✓18-✓5+✓20+✓1 2 C)✓25:✓16=✓36:✓9 D)✓12+✓27-5✓3 E)2✓3-✓75+2✓12
rút gọn biểu thức
A=2\(\sqrt{27}\)+5\(\sqrt{12}\)-3\(\sqrt{48}\)
B=\(\sqrt{147}\)+\(\sqrt{75}\)-4\(\sqrt{27}\)
C=3\(\sqrt{2}\)(4-\(\sqrt{2}\))+3(1-2\(\sqrt{2}\))2
D=2\(\sqrt{5}\)-\(\sqrt{125}\)-\(\sqrt{80}\)+\(\sqrt{605}\)
tinh : 2 can 27 - 3 can 48 + can 108
tìm x biết √x -3 -√9x-27 +2√16x-48 = 6