\(\dfrac{2}{3}+\dfrac{1}{3}:x=\dfrac{1}{2}\)
\(\dfrac{1}{3}:x=\dfrac{1}{2}-\dfrac{2}{3}\)
\(\dfrac{1}{3}:x=-\dfrac{1}{6}\)
\(x=\dfrac{1}{3}:\left(-\dfrac{1}{6}\right)\)
\(x=-2\)
Vậy ...
#AvoidMe
`2/3 +1/3 : x=1/2`
`=> 1/3 : x= 1/2 -2/3`
`=> 1/3 : x= 3/6 -4/6`
`=> 1/3 : x=-1/6`
`=> x=1/3 :(-1/6)`
`=> x=1/3 xx (-6)`
`=> x= -2`
Vậy `x=-2`