\(\dfrac{22\times9\times35}{18\times11\times49}\)
\(=\dfrac{11\times2\times9\times5\times7}{9\times2\times11\times7\times7}\)
\(=\dfrac{2\times7\times9\times11\times5}{2\times7\times9\times11\times7}\)
\(=\dfrac{5}{7}\)
#Toru
\(\dfrac{22x9x35}{18x11x49}=\dfrac{5}{7}\)