\(2x+\dfrac{7}{99}.\dfrac{8}{15}=\dfrac{106}{99}.\dfrac{8}{15}\)
=> \(2x+\dfrac{8}{15}.\dfrac{7}{99}-\dfrac{8}{15}.\dfrac{106}{99}=0\)
=> \(2x+\dfrac{8}{15}\left(\dfrac{7}{99}-\dfrac{106}{99}\right)=0\)
=> \(2x+\dfrac{8}{15}.\left(-1\right)=0\)
=> \(2x-\dfrac{8}{15}=0\)
=> \(2x=\dfrac{8}{15}\)
=> \(x=\dfrac{8}{15}:2=\dfrac{4}{15}\)