\(\left(2-3x\right)^2=\dfrac{9}{4}\)
\(\left(2-3x\right)^2=\perp\left(\dfrac{3}{2}\right)^2\)
\(\text{Vậy}2-3x=\dfrac{3}{2}\)
\(3x=2+\left(\dfrac{-3}{2}\right)=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}.\dfrac{1}{3}=\dfrac{1}{6}\)
\(\text{hoặc}2-3x=\left(\dfrac{-3}{2}\right)\)
\(3x=2+\dfrac{3}{2}=\dfrac{7}{2}\)
\(x=\dfrac{7}{2}.\dfrac{1}{3}=\dfrac{7}{6}\)
\(\Rightarrow x\in\left\{\dfrac{1}{6};\dfrac{7}{6}\right\}\)
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