Bài 1 đặt x2 = a rồi giải bình thường
Bài 2 đặt a=x/(x2 +5x - 5) rồi giải bình thường
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1)\(-x^2+4x-6+\frac{21}{x^2-4x+10}=0\)
2 ) \(\frac{3x}{x^2+5x-5}+\frac{x^2+5x-5}{x}+4=0\)
Chi tiết giùm mình nhá
giải phương trình:frac{2x}{6x^2-x+3}+frac{5x}{4x^2+5x+2}+frac{x}{2x^2+3x+1}frac{1}{3}b, frac{1}{x+1}+frac{2}{x+2}+frac{1}{x+3}frac{1}{x+4}+frac{2}{x+5}+frac{1}{x+6}c, x^2+frac{9x^2}{left(x+3right)^2}7d,frac{1}{x-1}+frac{1}{x}+frac{1}{x+1}+frac{1}{x+2}+frac{1}{x+3}0e,frac{9x}{x^2-2x+3}frac{5x^2+9x+15}{x^2+3x+3}
Đọc tiếp
giải phương trình:\(\frac{2x}{6x^2-x+3}+\frac{5x}{4x^2+5x+2}+\frac{x}{2x^2+3x+1}=\frac{1}{3}\)
b, \(\frac{1}{x+1}+\frac{2}{x+2}+\frac{1}{x+3}=\frac{1}{x+4}+\frac{2}{x+5}+\frac{1}{x+6}\)
c, \(x^2+\frac{9x^2}{\left(x+3\right)^2}=7\)
d,\(\frac{1}{x-1}+\frac{1}{x}+\frac{1}{x+1}+\frac{1}{x+2}+\frac{1}{x+3}=0\)
e,\(\frac{9x}{x^2-2x+3}=\frac{5x^2+9x+15}{x^2+3x+3}\)
1 : giải ptr : \(\frac{x+2}{x-2}-\frac{2x-1}{x^2+3x+2}=\frac{5}{2}\)
2 giải ptr :
a, \(\left(x-2\right)\left(x^2+5x-7\right)=0\)
b, \(x^3+3x^2-4x-12=0\)
c, ( x+1 ) ( x+2 ) (x+4 ) ( x+5 )=40
giai phuong trinh a) \(\left(\frac{x+3}{x+2}\right)^2+6\cdot\left(\frac{x-3}{x-2}\right)^2-5\cdot\frac{x^2-9}{x^2-4}=0\)
b)(12x-1)*(x-1)*(4x-1)*(3x-1)=330
c)\(\frac{4x}{x^2+5x+3}+\frac{5x}{x^2-5x+3}=\frac{-3}{2}\)
1) sqrt{x-1}-sqrt{2xleft(x-1right)}0 02)sqrt{5x^2}2x-13) sqrt{x+1}+sqrt{9x+9}44) sqrt{x-2}-sqrt{xleft(x-2right)}05)frac{sqrt{2x-3}}{sqrt{x-1}}26) frac{sqrt{5x+7}}{sqrt{x+3}}47) sqrt{5x-5}-sqrt{35}0Mình đang cần rất gấp(
Đọc tiếp
1) \(\sqrt{x-1}-\sqrt{2x\left(x-1\right)}=0\) 0
2)\(\sqrt{5x^2}=2x-1\)
3) \(\sqrt{x+1}+\sqrt{9x+9}=4\)
4) \(\sqrt{x-2}-\sqrt{x\left(x-2\right)}=0\)
5)\(\frac{\sqrt{2x-3}}{\sqrt{x-1}}=2\)
6) \(\frac{\sqrt{5x+7}}{\sqrt{x+3}}=4\)
7) \(\sqrt{5x-5}-\sqrt{35}=0\)
Mình đang cần rất gấp=(
1. \(1+\sqrt{3x-1}=3x\)
2. \(\sqrt{2+\sqrt{3x-5}=\sqrt{x+1}}\)
3.\(\sqrt{\frac{5x+7}{x+3}}=4\)
4. \(\frac{\sqrt{5x+7}}{\sqrt{x+3}}=4\)
5.\(\sqrt{5x^2}=2x+1\)
\(\left(\frac{2}{\sqrt{x}-2}+\frac{3}{2\sqrt{x}+1}-\frac{5\sqrt{x}-7}{2x-3\sqrt{x}-2}\right)\): \(\frac{2\sqrt{x}+3}{5x-10\sqrt{x}}\)(với x >0, x khác 4)
1)x^3 -2x-1
2) x^3 +3x^2 -4
3) x^3y^3 +x^2y^2 +4
4) x^3 + 5x^2 -9xy^2, +5y^3
5) x^4 + x^3 + 6x^2 + 5x + 5
Giai pt \(a,4\sqrt{x+1}=x^2+5x+4\)
\(b,\sqrt{4x+1}-\sqrt{3x-2}=\frac{x+3}{5}\)
\(c,2x^2-5x+5=\sqrt{5x-1}\)