\(\Leftrightarrow x-3\left(x-3\right)=3\)
=>x-3x+9=3
=>-2x=-6
hay x=3(loại)
ĐK : x ≠ 3
\(\Leftrightarrow\dfrac{x}{x\left(x-3\right)}-\dfrac{3\left(x-3\right)}{x\left(x-3\right)}=\dfrac{3}{x\left(x-3\right)}\)
\(\Leftrightarrow x-3\left(x-3\right)=3\)
\(\Leftrightarrow x-3x+9=3\)
\(\Leftrightarrow-2x=-6\)
\(\Leftrightarrow x=3\left(L\right)\)
Vậy : S = ∅