\(19\dfrac{1}{3}\times33\dfrac{1}{3}\)
\(=\dfrac{58}{3}\times\dfrac{100}{3}\)
\(=\dfrac{5800}{9}\)
\(\dfrac{3}{8}.19\dfrac{1}{3}-\dfrac{3}{8}.33\dfrac{1}{3}\)
Thực hiện phép tính (bằng cách hợp lý nếu có thể)
a) \(1\dfrac{4}{23}+\dfrac{5}{21}-\dfrac{4}{23}+0,5+\dfrac{16}{21}\)
b) \(\dfrac{3}{7}.19\dfrac{1}{3}-\dfrac{3}{7}.33\dfrac{1}{3}\)
c) \(9.\left(-\dfrac{1}{3}\right)^3+\dfrac{1}{3}\)
d) \(15\dfrac{1}{4}:\left(-\dfrac{5}{7}\right)-25\dfrac{1}{4}\left(-\dfrac{5}{7}\right)\)
\(\dfrac{1}{2}\) . \(x\) + \(\dfrac{3}{5}\) . (\(x\) - 2) =3
3 - (\(\dfrac{1}{6}\) - \(x\)) . \(\dfrac{2}{3}\) = \(\dfrac{2}{3}\)
\(39\dfrac{1}{3}:\dfrac{4}{5}-19\dfrac{1}{3}:\dfrac{4}{5}\)
Tinh
a)M=\(\dfrac{2012-\dfrac{1}{9}-\dfrac{2}{10}-\dfrac{3}{11}-...-\dfrac{2012}{2020}}{\dfrac{1}{27}+\dfrac{1}{30}+\dfrac{1}{33}+...+\dfrac{1}{6060}}\)
b)N=\(\dfrac{\dfrac{1}{1.300}+\dfrac{1}{2.301} +\dfrac{1}{3.302}+...+\dfrac{1}{101.400}}{\dfrac{1}{1.102}+\dfrac{1}{2.103}+\dfrac{1}{3.104}+...+\dfrac{1}{299.400}}\)
A=\(\left[\dfrac{1\dfrac{11}{31}.4\dfrac{3}{7}-\left(15-6\dfrac{1}{3}.\dfrac{2}{19}\right)}{4\dfrac{5}{6}+\dfrac{1}{6}\left(12-5\dfrac{1}{3}\right)}.\left(-1\dfrac{14}{93}\right)\right].\dfrac{31}{50}\)
bài 2: 1, \(\left(\dfrac{5}{6}\right)^{10}.\left(\dfrac{3}{10}\right)^{10}\)2,\(\left(\dfrac{4}{7}\right)^{19}:\left(\dfrac{-12}{35}\right)^{19}\) 3,\(\left(\dfrac{-3}{7}\right)^7:\left(\dfrac{-3}{5}\right)\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
giúp em với ạ. em cần gấp. camon
Tính bằng cách hợp lí:
a, 2 - (\(\dfrac{3}{7}\)+\(\dfrac{1}{3}\)) - (2- \(\dfrac{4}{3}\)+\(\dfrac{2}{7}\)) + 2 - (4-\(\dfrac{5}{7}\))
b, \(\dfrac{-3}{13}\) . (\(\dfrac{44}{33}\)+\(\dfrac{4444}{3030}\)+\(\dfrac{444444}{404040}\))
