Ta có: \(\dfrac{-1}{6}=\dfrac{3}{2}\cdot x\)
\(\Leftrightarrow x=\dfrac{-1}{6}:\dfrac{3}{2}=\dfrac{-1}{6}\cdot\dfrac{2}{3}=\dfrac{-1}{9}\)
Vậy: \(x=-\dfrac{1}{9}\)
\(\dfrac{-1}{6}=\dfrac{3}{2}.x\)
\(\dfrac{-1}{6}:\dfrac{3}{2}=x\)
\(\dfrac{-1}{6}.\dfrac{2}{3}=x\)
\(\dfrac{-1}{9}=x\)
\(x=\dfrac{-1}{9}\)(Không cần thiết)