\(\left(15,3-x\right)^8=\left(x-15,3\right)^7\)
\(\Rightarrow\left(x-15,3\right)^8=\left(x-15,3\right)^7\)
\(\Rightarrow\left(x-15,3\right)^8-\left(x-15,3\right)^7=0\)
\(\Rightarrow\left(x-15,3\right)^7\left(x-15,3-1\right)=0\)
\(\Rightarrow\left(x-15,3\right)\left(x-16,3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-15,3=0\\x-16,3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=15,3\\x=16,3\end{cases}}}\)
Vậy \(x\in\left\{15,3;16,3\right\}\)
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