\(\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\)
=>\(\dfrac{1}{3}x+\dfrac{2}{5}x-\dfrac{2}{5}=0\)
=>\(\dfrac{11}{15}x=\dfrac{2}{5}\)
=>\(x=\dfrac{2}{5}:\dfrac{11}{15}=\dfrac{2}{5}\cdot\dfrac{15}{11}=2\cdot\dfrac{6}{11}=\dfrac{12}{11}\)
$#flo$
`1/3 x + 2/5(x-1) = 0`
`=> 1/3x + 2/5x - 2/5 = 0`
`=> 11/15x = 2/5`
`=> x = 6/11`