\(=\dfrac{-2}{6}+\dfrac{15}{6}=\dfrac{13}{6}\)
\(=\dfrac{-2}{6}+\dfrac{15}{6}=\dfrac{13}{6}\)
a,1/3 .(x-2/5)=3/4 b, 7/3:(x-2/3)=4/5 c,1/3.(x-2/5)=4/5 d, 2/3.(x-1/2)-1/4.(x-2/5)=7/3 e,3/7 .(x-2/3)+1/2=5/4.(x-2) f,1/2.(x-3)+1/3.(x-4)+1/4.(x-5)=1/5 g,[2/3.(x-1/2)-4/5]:(x-1/3)=21/5 h, {x-[1/2.(x-3)+11/5]}:(x-1/2)=3/5 i,x.(x-2/5)-(x+2).x+11/4=4/3
a,1/1*2+1/2*3+1/3*4+1/4*5+......+1/9*10
b,2/1*3+2/3*5+2/5*7+2/7*9+2/9*11
c,3/1*3+3/3*5+3/5*7+3/7*9+3/9*11
d,5/1*3+5/3*5+5/5*7+5/7*9+5/9*11
Giúp mình với
so sánh 1+5+5^2+..+5^9/1+5+5^2+5^3+...+5^8 với 1+3+3^2+..+3^9/1+3+3^2+3^3+...+3^8
a,-2\3x+1\5=1\10
b,2|1\2x-3\8|-3\2=1\4
c,-5(x+1\5)-1\2(x-2\3)=3\2x-5\6
d,3(x-1\2)- 5(x+3\5)=-x+1\5
e,3\4-2.|2x-0,125|=2
f,2|1\2x-1\3|-3\2=1\4
g,4\5-1\2x=1\10
so sanh:A=(1+5+5^2+..+5^9/)1+5+5^2+...+5^8)voi B=1+3+3^2+..+3^9/1+3+3^2+..+3^9
so sanh:A=(1+5+5^2+..+5^9/)1+5+5^2+...+5^8)voi B=1+3+3^2+..+3^9/1+3+3^2+..+3^9
Tìm x
a, ( 3 . x -1 ) . ( -1/2 .x + 5 ) = 0
b, 3. ( x - 1/2 ) - 5 ( x + 3 /5 ) = x + 1 /5
c, -5 . ( x + 1/5 ) - 1/2 . ( x - 2/3 ) = 3/2 . x - 5/6
d,3. ( 3 . x - 1/2 ) mũ 3 + 1/9 = 0
a) 4 3/8 + 5 2/3 b) 2 3/8 + 1 1/4 + 3 6/7
c) 2 3/8 - 1 1/4 + 5 1/3 d) (5/2 + 1/3) : ( 1 - 1/2)
e) (5/2 - 1/3) x 9/2 - 6/7
Cho A=(1+5+5^2+5^3+...+5^2018)/(1+5+5^2+5^3+...+5^2019)
B=(1+3+3^2+3^3+...+3^2018)/(1+3+3^2+3^3+...+3^2019)
Hãy so sánh A và B
Bài 1:thực hiện phép tính(hợp lí nếu có thể):
1, -5/12 x 2/11 + -5/12 x 9/11 + 5/12
2, -3/5 : 7/5 - 3/5 : 7/5 + 2 3/5
3, 1/2+ 3/4 - ( 3/4 - 4/5)
4, 2/3 + 1/3 x ( -4/9 + 5/6)
5, -3/7 x 5/9 + 4/9 x -3/7 + ( - 2022) ^ 0
6,0,75 - ( 2 1/3 + 0,75) + 3 ^ 2 x ( -1/9)
7, 2 6/7 x [(-7/5 - 3/2 : -5/-4) + ( 3/2)^2]
8,2/7 + 5/7 x ( 3/5 - 0,25 ) x ( -2)^2 + 35%
9, 1 13/15 x 0,75 - ( 11/20 + 25%): 1 2/5
10, ( -2,4 + 1/3 ) : 3 1/10 + 75% : 1 1/2
11.5/3 - 5/7 + 5/9 / 10/3 - 10/7 + 10/9