`13/20+(3/5+x)=5/6`
`3/5+x=5/6-13/20`
`3/5+x=11/60`
`x=11/60-3/5`
`x=-5/12`
\(\dfrac{13}{20}+\left(\dfrac{3}{5}+x\right)=\dfrac{5}{6}\\ \dfrac{3}{5}+x=\dfrac{5}{6}-\dfrac{13}{20}\\ \dfrac{3}{5}+x=\dfrac{11}{60}\\ x=\dfrac{11}{60}-\dfrac{3}{5}\\ x=-\dfrac{5}{12}\)
`13/20 + (3/5 + x) = 5/6`
`=> 3/5 + x = 13/20 - 5/6`
`=> 3/5 + x = 11/60`
`=> x = 11/60 - 3/5`
`=> x = -5/12`
Vậy `x = -5/12`