\(\dfrac{1}{3}-\dfrac{5}{7}\cdot\dfrac{1}{5}-\left|-\dfrac{4}{3}\right|+2020^0 \)
= \(\dfrac{1}{3}-\dfrac{4}{3}-\dfrac{1}{7}+1\)
= \(-1+1-\dfrac{1}{7}\)
= \(-\dfrac{1}{7}\)
\(\dfrac{1}{3}-\dfrac{5}{7}.\dfrac{1}{5}-\left|\dfrac{-4}{3}\right|+2020^0\)
\(=\dfrac{1}{3}+\dfrac{-5}{7}.\dfrac{1}{5}+\dfrac{-4}{3}+1\)
\(=\dfrac{1}{3}+\dfrac{-1}{7}+\dfrac{-4}{3}+1\)
\(=\dfrac{4}{21}+\dfrac{-4}{3}+1\)
\(=\dfrac{-8}{7}+1\)
\(=\dfrac{-1}{7}\)