\(\frac{1}{2}.x+\frac{3}{5}.\left(x-2\right)=3
\)
\(\frac{1}{2}x+\frac{3}{5}x-\frac{3}{5}.2=3\)
\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)
\(\left(\frac{5}{10}+\frac{6}{10}\right).x=3+\frac{6}{5}\)
\(\frac{11}{10}.x=\frac{21}{5}\)
x =\(\frac{21}{5}:\frac{11}{10}\)
x=\(\frac{21}{5}.\frac{10}{11}\)
x-\(\frac{42}{11}\)
1. x/y-2=3/2 và x-y=4
2. x-4/y+2=1/2 và x+y=5
3. 3/x-2=2/y+2 và x+y=5
4.3/x-2=2/y+2 và x+y=1
5.x+2/y+3=5/6 và x-y=1
6. x-1/y+4=3/4 và 2x=3y
7. x-1/y+4=3/4 và 2x=3y+2
3(x-1/2)-5(x+3/5)= -x+1/5
-5(x+1/5)-1/2(x-2/3)=3/2x-5/6
-3/7:x=7/5
x. 2/3=-3/4
3/5-2/3:x =-7/4
x:7/6+-1/3=2/3
Tìm x:
\(x.\frac{1}{2}-x.\frac{2}{3}+x.\frac{3}{4}-x.\frac{5}{6}=\frac{5}{6}-\frac{3}{4}+\frac{2}{3}-\frac{1}{2}\)
help me pleas
-5(x+1/5)-1/2(x-2/3)=3/2x-5/6
3(x-1/2)-5(x+3/5)= -x+1/5
Bất phương trình logarit
$$1) \sqrt{log_{1/2}^{2} \frac{2x}{4-x} - 4} \leq \sqrt{5}$$
$$2)log_{2}(x-1)^{2} > 2log_{2} (x^{3} +x +1)$$
$$3)\frac{1}{log_{2}(4x)^{2} +3 } + \frac{1}{log_{4} 16x^{3}-2} <-1$$
$$4)log_{2} (4^{x}+4) < log_{\frac{1}{2}} (2^{x+1} -2)$$
tìm x :
1/2 .x + 3/5 .( x- 2 ) = 3
