\(\dfrac{1}{2}=x+\dfrac{1}{3}x\)
=>\(\dfrac{4}{3}x=\dfrac{1}{2}\)
=>\(x=\dfrac{1}{2}:\dfrac{4}{3}=\dfrac{1}{2}\cdot\dfrac{3}{4}=\dfrac{3}{8}\)
\(\dfrac{1}{2}=\dfrac{x+1}{3x}\\ =>3x=2\left(x+1\right)\\ =>3x=2x+2\\ =>3x-2x=2\\ =>x=2\)
\(\dfrac{1}{2}=x+\dfrac{1}{3}x\)
=>\(\dfrac{4}{3}x=\dfrac{1}{2}\)
=>\(x=\dfrac{1}{2}:\dfrac{4}{3}=\dfrac{1}{2}\cdot\dfrac{3}{4}=\dfrac{3}{8}\)
\(\dfrac{1}{2}=\dfrac{x+1}{3x}\\ =>3x=2\left(x+1\right)\\ =>3x=2x+2\\ =>3x-2x=2\\ =>x=2\)
Cho R(x) = 2x 2 + 3x - 1; M(x) = x 2 - x 3 thì R(x) - M(x)=
A.-3x 3 + x 2 + 3x – 1 B. -3x 3 - x 2 + 3x – 1
B. 3x 3 - x 2 + 3x – 1 D. x 3 + x 2 + 3x + 1
b1:
[4+2x]=-3x [3x-1]+2=x
[x+15]+1=3x [2x-5]+x=2
b2:
[2x-5]=x+1 [3x-2]-1=x
[3x-7]=2x+1 [2x-1]+1=x
Tìm nghiệm : a) (2x-3).(2x+3) B)(x-4).(x-1).(x-2) C)2x(3x-1)-3x(5+2x) D)(3x-2).(3x+2)-4.(x-1)
Bài 2 Tìm x biết 1, (2x-2).(3x+1)-(3x-2).(2x-3)=5 2,(1-3x).(3x-5)-(2x-4)(2-3x)=x-6 3,(2x-1).(4x^2+2x+1)-(2x+1)(4x^2-2x+1)=5x+6 Giúp tớ với
B1. Tính giá trị: A=(x+2)^2 - (x-2)^2 với x=125
B2. Thu gọn:
a, 2x.(2x-1)^2 - 3x.(x+3).(x-3) - 4x.(x+1)^2
b. (3x+1)^2 - 2.(3x+1).(3x+5) + (3x+5)^2
B3: Tìm x biết (x+2)^2 - x^2 +4=0
làm tính chia:
a)( x^2 +3x -2):(x-1)
b) (3x^2-3x+1):(x+2)
1)2x2(-x+3x2-5)-(7x2+3x-2)
2)-3x(1-x2)-5x(x2+2+x+1)
3)-2x2(-x5)+3x(x2+x+1)
1) Tìm x,biết :
a) 3/2 . |x-5/3| - 4/5 = 4/3 . |x-5/3| + 1
b) 2.|3x +1| = 1/3 . |3x + 1| +5
c) 1/4 - 5/2 . | 3x - 1/5| = 2/3. |3x - 1/5| - 2/3
Tìm x:
a) x(2x - 1)(x + 5) - (2x^2 + 1)(x + 4,5) = 3,5
b) 3x^2 - 3x(x - 2) = 36
c) (3x^2 - x + 1)(x - 1) + x^2(4 - 3x) = 5/2
Giúp mình với (T^T),
Tìm x biết
a,
\(|x-1|+|x-2|+|x-3|=2\)
b,
\(|3x+\frac{1}{2}|+|3x+\frac{1}{6}|+|3x+\frac{1}{12}|+|3x+\frac{1}{20}|+...+|3x+380|=58x\)