Question

(1/2x + 1/4) . (2x - 1/3) =0                  

                                   tim x

Answer 1

`TH_1: 1/2 x + 1/4 = 0`

`=> 1/2(x + 1/2) = 0`

`=> x + 1/2 = 0`

`=> x = -1/2`

`TH_2: 2x - 1/3 =0`

`=> 2x = 1/3`

`=> x = 1/6`

Vậy `S = {1/6, -1/2}`

Answer 2

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x+\dfrac{1}{4}=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x=-\dfrac{1}{4}\\2x=\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{6}\end{matrix}\right.\)

Answer 3

`(1/2x + 1/4) . (2x - 1/3) = 0`

 ta có 2 trường hợp là : 

`=>`\(\left\{{}\begin{matrix}\dfrac{1}{2}x+\dfrac{1}{4}=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\)

TH1:

`1/2x + 1/4 = 0`

`=> 1/2x      = -1/4`

`=>     x       = -1/2`

________________

TH2:

`2x - 1/3 = 0`

`=> 2x    = 1/3`

`=>  x      = 1/6`

=> `x = {-1/2 ; 1/6}`