Question

 

(128–  32 * 4 ) * (1+2+3+......+99+100) 

 

Answer 1

(128 - 32*4)*(1 + 2 + 3 +... + 99 + 100)

= (128 - 128) *(1 + 2 + 3 +... + 99 + 100)

= 0 x (1 + 2 + 3 +... + 99 + 100)

= 0

Chúc em học tốt !!!

Answer 2

\(\text{= 0 nka em HT~}\)

Answer 3

\(\left(128-32\times4\right)\times\left(1+2+3+.....+99+100\right).\)

\(=\left(128-128\right)\times\left(1+2+3+.....+99+100\right).\)

\(=0\times\left(1+2+3+.....+99+100\right).\)

\(=0\)

Answer 4

(128-32*4)*(1+2+3+......+99+100)

=(128-128)*(1+2+3+......+99+100

=0*(1+2+3+......+99+100)

=0

Answer 5

( 128 - 32 x 4 ) x ( 1 + 2 + 3 + ... + 99 + 100 )

= (  128 - 128 ) x  ( 1 + 2 + 3 + ... + 99 + 100 )

= 0 x ( 1 + 2 + 3 + ... + 99 + 100 )

= 0