Question

1/27-(x+1/2)^3 =0

Answer 1

\(\dfrac{1}{27}-\left(x+\dfrac{1}{2}\right)^3=0\\ \Leftrightarrow\left(x+\dfrac{1}{3}\right)^3=\dfrac{1}{27}\\ \Leftrightarrow\left(x+\dfrac{1}{3}\right)^3=\left(\dfrac{1}{3}\right)^3\\ \Rightarrow x+\dfrac{1}{3}=\dfrac{1}{3}\\ \Leftrightarrow x=0\)

Answer 2

1/27-(x+1/2)³=0

=> (x+1/2)³=1/27

=> x+1/2=1/3

=> x=-1/6