\(\dfrac{12}{5}+3=\dfrac{12}{5}+\dfrac{15}{5}=\dfrac{12+15}{5}=\dfrac{27}{5}\)
\(\dfrac{12}{5}+3=\dfrac{12}{5}+\dfrac{3\times5}{1\times5}=\dfrac{12}{5}+\dfrac{15}{5}=\dfrac{12+15}{5}=\dfrac{27}{5}\)
\(\dfrac{12}{5}+3\)
=\(\dfrac{36}{15}\)+\(\dfrac{45}{15}\)
=\(\dfrac{81}{15}\)=\(\dfrac{17}{5}\)