\(\left(1.25-\dfrac{3}{7}x\right)\left(-\dfrac{5}{4}x+\dfrac{14}{9}\right)=0\)
\(\Rightarrow1.25-\dfrac{3}{7}x=0;-\dfrac{5}{4}x+\dfrac{14}{9}=0\)
*) \(1.25-\dfrac{3}{7}x=0\)
\(25-\dfrac{3}{7}x=0\)
\(\dfrac{3}{7}x=25\)
\(x=25:\dfrac{3}{7}\)
\(x=\dfrac{175}{3}\)
*) \(-\dfrac{5}{4}x+\dfrac{14}{9}=0\)
\(-\dfrac{5}{4}x=-\dfrac{14}{9}\)
\(x=-\dfrac{14}{9}:\left(-\dfrac{5}{4}\right)\)
\(x=\dfrac{56}{45}\)
Vậy \(x=\dfrac{56}{45}\); \(x=\dfrac{175}{3}\)