Question

(1+2/3).(1+2/5).(1+2/7)...(1+2/2021)

Answer 1

ai giúp mik với

 

Answer 2

bn ơi

Answer 3

mk chx hiểu đề lắm

Answer 4

\(\left(1+\dfrac{2}{3}\right)\left(1+\dfrac{2}{5}\right)\left(1+\dfrac{2}{7}\right)...\left(1+\dfrac{2}{2021}\right)\)
\(=\left(\dfrac{3+2}{3}\right)\left(\dfrac{5+2}{3+2}\right)\left(\dfrac{7+2}{5+2}\right)...\left(\dfrac{2021+2}{2019+2}\right)\)
\(=\dfrac{\left(3+2\right)\left(5+2\right)\left(7+2\right)...\left(2021+2\right)}{3\left(3+2\right)\left(5+2\right)...\left(2019+2\right)}\)
\(=\dfrac{2021+2}{3}=\dfrac{2023}{3}\)
Chúc bạn học tốt! Nhớ tick cho mình nha ^.^

Answer 5

^{2023  TRÊN 3 NHA}