Đặt \(A=\dfrac{1}{2^2}+\dfrac{1}{3^2}+...+\dfrac{1}{200^2}\)
=>\(A< \dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{199\cdot200}\)
=>\(A< 1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{199}-\dfrac{1}{200}\)
=>\(A< 1-\dfrac{1}{200}=\dfrac{199}{200}< 1\)
2.
E=1+1/2.(1+2)+1/3.(1+2+3)+...+1/200.(1+2+...+200)
tinh B=1+1/2(1+2)+1/3(1+2+3)+1/4+(1+2+3+4)+...+1/200(1+2+....+200)
thuc hien tinh :E=1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+.......+1/200(1+2+3+.....+200)
Thực hiện tính:
E=1+1/2.(1+2)+1/3.(1+2+3)+1/4.(1+2+3+4)+.....+1/200(1+2+...+200)
1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)........+1/200(1+2+3+4+5+6+7+.....+200)
thực hiện phép tính
E=1+1/2(1+2)+1/2(1+2+3)+1/4(1+2+3+4)+.....+1/200(1+2+3+....+200)
\(1+\dfrac{1}{2}\left(1+2\right)+\dfrac{1}{3}\left(1+2+3\right)+\dfrac{1}{4}\left(1+2+3+4\right)+...+\dfrac{1}{200}\left(1+2+...+200\right)\)
Tính : -1-1/2.(1+2)-1/3.(1+2+3)-...-1/200.(1+2+3+...+200)
Mong các bạn giúp mình nhiều nha !!!!
a)Tính tổng :E=1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+...+1/200(1+2+3+4+...+200)
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Tính: \(E=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+...+\frac{1}{200}\left(1+2+3+...+200\right)\)
