\(\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{8}\right)^2\)
\(=>\left(\dfrac{1}{2}\right)^n=\left[\left(\dfrac{1}{2}\right)^3\right]^2\)
\(=>\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{2}\right)^6\)
\(\Rightarrow n=6\)
\(\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{8}\right)^2 \Rightarrow\left(\dfrac{1}{2}\right)^n=\dfrac{1}{64} \Rightarrow\left(\dfrac{1}{2}\right)^n=\left(\dfrac{1}{2}\right)^6\Rightarrow n=6\)