Lời giải:
$(\frac{1}{2}+2x)(2x-3)=0$
$\Leftrightarrow \frac{1}{2}+2x=0$ hoặc $2x-3=0$
$\Rightarrow x=\frac{-1}{4}$ hoặc $x=\frac{3}{2}$
(\(\dfrac{1}{2}\) + 2\(x\))(2\(x\) - 3) =0
\(\left[{}\begin{matrix}\dfrac{1}{2}+2x=0\\2x-3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-\dfrac{1}{2}\\2x=3\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-\dfrac{1}{2}:2\\x=3:2\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=\dfrac{3}{2}\end{matrix}\right.\)
\(\left(\dfrac{1}{2}+2x\right).\left(2x-3\right)=0\)
- Ta có 2 trường hợp:
\(\dfrac{1}{2}+2x=0\) ⇒ \(x=-\dfrac{1}{4}\)
\(2x-3=0\) ⇒ \(x=1,5\)
