1000 z thì :>
1+1+1+996+1+3=1003 hoặc
1+1+1+1000+1+3=1007 :Đ
1000 z thì :>
1+1+1+996+1+3=1003 hoặc
1+1+1+1000+1+3=1007 :Đ
(1/3+1/3^2+1/3^3+1/3^4).3^5+(1/3^5+1/3^6+1/3^7+1/3^8).3^9+.....+(1/3^97+1/3^98+1/3^99+1/3^100).3^101
so sánh
a)A=1/2^1+1/2^2+1/2^3+...+1/2^49+1/2^50 với 1
b)B=1/3^1 +1/3^2+1/3^3...+1/3^99+1/3^100 với 1/2
c)C=1/4^1+1/4^2+1/4^3+...+1/4^999+1/4^1000 với 1/3
a) [ 6.(-1/3)^3 - 3. (-1/3)+ 1] - (-1/3 - 1)
b) ( 6^3+ 3. 6^2+ 3^3 ) : 13
c) 9/10-1/90-1/72-1/56-1/42-1/30-1/20-1/12-1/6-1/2
(1/125-1/1^3).(1/125-1/2^3).(1/125-1/3^3)...(1/125-1/25^3)
(1/125 - 1/ 1^3).(1/125 - 1/ 2^3).(1/125 - 1/ 3^3)....(1/125 - 1/ 25^3).
Tính giá trị của biểu thức:
A=(1/3+1,3^2+1/3^3+1/3^4).3^5+(1/3^5+1/3^6+1/3^7+1/3^8).3^9+...+(1/3^97+1/3^98+1/3^99+1/3^100).3^101
(1+1/1+2)(1+1/1+2+3)(1+1/1+2+3+4)...(1+1/1+2+3+...+100)
tính C: C=(1/125-1/1^3)(1/125-1/2^3)(1/125-1/3^3)...(1/125-1/25^3)
1.
a) 1/1.4+1/4.7+1/7.10+...+1/100.103
b)-1/3+-1/15+-1/35+-1/63+...+-1/9999
2.
3/1.4+3/4.7+3/7.10+...+3/94.97+3/97.100
a)(5+1/5-2/9)-(2-1/23-3/35+5/6)-(8+2/7-1/18)
b) 1/3-3/4(-3/5+1/64- -2/9-1/36+1/15
c) -5/7-(-5/67)+13/10+1/2+(-1/6)+1 3/14-(-2/5)
d)3/5:(-1/15-1/6)+3/5:(-1/3-1 1/15)