\(\Leftrightarrow\left(10-x\right)\cdot2+7=\left(3+2\right)\cdot3=15\)
=>10-x=4
hay x=6
[(10-x).2+7]:3 = 3+2 [(10-x).2+7]:3 = 5 (10-x).2+7 = 5.3 (10-x).2+7=15 (10-x).2 = 15-7 (10-x).2 = 8 10-x = 4 x =10-4=6
[( 10 - x ) . 2 + 7 ] : 3 - 2 = 3
[(10 - x ) . 2 + 7 ] : 3 = 3 + 2
( 10 - x ) . 2 + 7 : 3 = 5
( 10 - x ) . 2 + 7 = 5 . 3
( 10 - x ) . 2 + 7 = 15
( 10 - x ) . 2 = 15 - 7
( 10 - x ) . 2 = 8
10 - x = 8 : 2
10 - x = 4
x = 10 - 4
x = 6