Question

1. Tìm x thuộc Z biết:

a) (-2012) . (x+3) = 0

Answer 1

a) (-2012) . (x + 3) = 0

=> x + 3 = 0

=> x = 0 - 3

=> x = -3

Vậy x = -3

Answer 2

a, => x+3 = 0 : (-2012) = 0

=> x = 0 - 3 = -3

Vậy x = -3

Tk mk nha

Answer 3

(-2012) .(x+3)=0

<=> \(\hept{\begin{cases}-2012\\x+3=0\end{cases}}\)

<=>\(\hept{\begin{cases}-2012\\x=0-3\end{cases}}\)

<=>\(\hept{\begin{cases}-2012\\x=-3\end{cases}}\)

Answer 4

a) \(\left(-2012\right)\left(x+3\right)=0\)

\(\Rightarrow x+3=0\)

\(\Rightarrow x=-3\)

vậy \(x=-3\)

Answer 5

(-2012).(x + 3) = 0

x + 3 = 0 : (-2012)

x + 3 = 0 

x = 0 - 3

 x = -3

vậy_____