Question

1. Tìm x, biết
a) \(x:\dfrac{16}{7}+\dfrac{1}{8}=\dfrac{4}{3}\)
b)\(\dfrac{1}{3}+x:\dfrac{1}{3}=1\)

Answer 1

\(a,x:\dfrac{16}{7}=\dfrac{4}{3}-\dfrac{1}{8}\\ x:\dfrac{16}{7}=\dfrac{32-3}{24}\\ x:\dfrac{16}{7}=\dfrac{29}{24}\\ x=\dfrac{29}{24}.\dfrac{16}{7}\\ x=\dfrac{58}{21}\\ b,x:\dfrac{1}{3}=1-\dfrac{1}{3}\\ x:\dfrac{1}{3}=\dfrac{2}{3}\\ x=\dfrac{2}{3}.\dfrac{1}{3}\\ x=\dfrac{2}{9}\)

Answer 2

1) \(x:\dfrac{16}{7}+\dfrac{1}{8}=\dfrac{4}{3}\)

\(\Rightarrow x:\dfrac{16}{7}=\dfrac{4}{3}-\dfrac{1}{8}\)

\(\Rightarrow x:\dfrac{16}{7}=\dfrac{29}{24}\)

\(\Rightarrow x=\dfrac{58}{21}\)

2) \(\dfrac{1}{3}+x:\dfrac{1}{3}=1\)

\(\Rightarrow x:\dfrac{1}{3}=\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{2}{9}\)