Question

1. tìm x, biết:

a) ( 2x-1)^2= (1/2-x) ^2

Answer 1

x=1/2

Answer 2

(2x-1)²=(\(\dfrac{1}{2}\)-x)²

^{\(\Leftrightarrow\)}4x²-4x+1=\(\dfrac{1}{4}\)-x+x²

^{\(\Leftrightarrow\)}3x²-3x+\(\dfrac{3}{4}\)=0

\(\Leftrightarrow\)3(x²-x+\(\dfrac{1}{4}\))=0

\(\Leftrightarrow\)(x-\(\dfrac{1}{2}\))²=0

\(\Leftrightarrow\)x-\(\dfrac{1}{2}\)=0

\(\Leftrightarrow\)x=\(\dfrac{1}{2}\)