\(1+\dfrac{4}{5}+\dfrac{7}{6}+\dfrac{1}{5}=1+\left(\dfrac{4}{5}+\dfrac{1}{5}\right)+\dfrac{7}{6}=1+1+\dfrac{7}{6}=\dfrac{19}{6}\)
\(1+\dfrac{4}{5}+\dfrac{7}{6}+\dfrac{1}{5}=\dfrac{30}{30}+\dfrac{24}{30}+\dfrac{35}{30}+\dfrac{6}{30}=\dfrac{30+24+35+6}{30}=\dfrac{95}{30}=\dfrac{19}{6}\)