Nguyễn Huy Thắng giải sai rồi ,thế này mới đúng nè
1,\(\frac{1}{6}+\frac{1}{12}+.........+\frac{1}{72}\)
=\(\frac{1}{2.3}+\frac{1}{3.4}+.......+\frac{1}{8.9}\)
=\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.......+\frac{1}{8}-\frac{1}{9}\)
=\(\frac{1}{2}-\frac{1}{9}\)
=\(\frac{7}{18}\)
2,\(\frac{3}{1.4}+\frac{3}{4.7}+..........+\frac{3}{13.16}\)
=\(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+.........+\frac{1}{13}-\frac{1}{16}\)
=\(1-\frac{1}{16}\)
=\(\frac{15}{16}\)
2)đặt B= 3/1.4+3/4.7+3/7.10+3/10.13+3/13.16
\(B=3\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{16}\right)\)
\(B=3-\frac{15}{16}\)
\(B=\frac{45}{16}\)
1)
1/6+1/12+1/30+1/56+1/72
= 1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8
= 1/2-1/3+1/3-1/4+...+1/7-1/8
= 1/2-1/8
= 3/8
2)
3/1.4+3/4.7+3/7.10+3/10.13+3/13.16
= 1-1/4+1/4-1/7+..+1/13-1/16
= 1-1/16
= 15/16
mk nhé đầu tiên đó
1/6+1/12+1/30+1/42+1/56+1/72 = 61/180
3/1.4+3/4.7+3/7.10+3/10.13+3/13.16 = 15/16
úm ba la xin tích
Trần Thùy Trang giải tào lao 30=4*5 (troll quá mức)
1) 1 / 6 + 1 / 12 + 1 / 20 +1 / 30 + 1 / 42 + 1 / 56 + 1 / 72
= 1 / 2 . 3 + 1 / 3 . 4 + 1 / 4 . 5 +.....+ 1 / 8 . 9
= 1 - 1 / 2 + 1 / 2 - 1 / 3 + 1 / 4 - 1 / 5+.... + 1 / 8 - 1 / 9
= 1 - 1 / 9
= 8 / 9
2 ) 3 / 1 . 4 + 3 / 4 . 7 + 3 / 7 . 10+...+ 3 / 13 . 16
= 1 - 1 / 4 + 1 / 4 - 1 / 5 +.....+ 1 / 13 - 1 / 16
= 1 - 1 / 16
= 15 / 16
\(\frac{1}{6}+\frac{1}{12}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)
Thiếu đề hay sao ấy
Không có học trò dốt
Mà chỉ có thầy chưa giỏi