\(0,5x-\dfrac{2}{3}\left(x+1\right)=-\dfrac{1}{12}\\ \Leftrightarrow\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{2}{3}=-\dfrac{1}{12}\\ \Leftrightarrow\dfrac{-1}{6}x=\dfrac{7}{12}\\ \Leftrightarrow x=-\dfrac{7}{2}\)
Vậy x = -\(\dfrac{7}{2}\)
\(0,5\times\dfrac{-2}{3}.\left(x+1\right)=\dfrac{-1}{12}\)
\(\dfrac{1}{2}\times\dfrac{-2}{3}.\left(x+1\right)=\dfrac{-1}{12}\)
\(\dfrac{-2}{3}.\left(x+1\right)=\dfrac{-1}{12}:\dfrac{1}{2}\)
\(\dfrac{-2}{3}.\left(x+1\right)=\dfrac{-1}{6}\)
\(x+1=\dfrac{-1}{6}:\dfrac{-2}{3}\)
\(x+1=\dfrac{1}{4}\)
\(x=\dfrac{1}{4}-1\)
\(x=\dfrac{-3}{4}\)