\(a,Đk:x\le1\\ PT\Leftrightarrow-x+1=9\Leftrightarrow x=-8\left(tm\right)\\ b,ĐK:x\ge\dfrac{1}{2}\\ PT\Leftrightarrow\left[{}\begin{matrix}2\sqrt{x+3}=6\\\sqrt{2x-1}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x+3=9\\2x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\left(tm\right)\\x=\dfrac{1}{2}\left(tm\right)\end{matrix}\right.\)
a) ĐKXĐ: \(x\le1\)
\(pt\Leftrightarrow-x+1=9\Leftrightarrow x=-8\left(tm\right)\)
b) ĐKXĐ: \(x\ge\dfrac{1}{2}\)
\(pt\Leftrightarrow\left[{}\begin{matrix}2\sqrt{x+3}=6\\\sqrt{2x-1}=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x+3}=3\\2x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x+3=9\\x=\dfrac{1}{2}\left(tm\right)\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=6\left(tm\right)\\x=\dfrac{1}{2}\end{matrix}\right.\)